No, 7r and 2 are not like terms. Like terms have the same variable raised to the same power, which means they must have identical variable components. In this case, 7r contains the variable "r," while 2 is a constant without any variable.
You are searching for the value of r.-7r + 6 = 9 - 6r + 1Notice the 9 and the 1 on the right side. Since they are common factors (terms not attached to x), they can be added.-7r + 6 = -6r + 10Subtract 6 from both sides to eliminate the 6 on the left.-7r = -6r + 4Add 7r to both sides, leaving r-terms on only one side.0 = r + 4Subtract 4 from both sides, so one side is constant and the other is the variable.-4 = rThe answer is -4 is equal to r.
9r-1?
100 - 7r = 44 Subtract 100 from both sides: -7r = -56 Divide both sides by -7: r = 8
6p - pq 7pr factorizing = -1
63
It is a string of algebraic terms.
If that's the equation 6r + 7 = 13 + 7r, r = -6
7r-43 = -36
You are searching for the value of r.-7r + 6 = 9 - 6r + 1Notice the 9 and the 1 on the right side. Since they are common factors (terms not attached to x), they can be added.-7r + 6 = -6r + 10Subtract 6 from both sides to eliminate the 6 on the left.-7r = -6r + 4Add 7r to both sides, leaving r-terms on only one side.0 = r + 4Subtract 4 from both sides, so one side is constant and the other is the variable.-4 = rThe answer is -4 is equal to r.
how do i solve -3r+3r=-6(7+7r)-7(4-7r)
the answer is 7r.1 hope it helps
9r-1?
7(r-12) A 7 is taken out because it is a common factor to both terms.
100 - 7r = 44 Subtract 100 from both sides: -7r = -56 Divide both sides by -7: r = 8
12 + 8r - 6 = 7r - 5 - 3 8r +6 = 7r -8 r = -14
I think so.r2 + 7r + 6 = [ (r+6) (r+1) ]
7r = r + r + r + r + r + r + r or r7