All numbers have cube roots (not necessarily integral cube roots) so every prime has cube roots.
Not sure what answer you are looking for, but here are 4 types of roots in math. First is a square roots, next is cube roots, then the nth roots, and lastly rational roots.
No. The square roots of perfect squares are rational.
Yes.
Not necessarily. The cube roots of 4, 6 and 9 are all irrational (and different). But their product is 6, not just rational, but an integer.
All numbers have cube roots (not necessarily integral cube roots) so every prime has cube roots.
-39 has no rational roots.
Not sure what answer you are looking for, but here are 4 types of roots in math. First is a square roots, next is cube roots, then the nth roots, and lastly rational roots.
No. Lots of square roots are not rational. Only the square roots of perfect square numbers are rational. So for example, the square root of 2 is not rational and the square root of 4 is rational.
One of them is: -5 = -5/1 The other two cube roots are complex numbers.
No. The square roots of perfect squares are rational.
Rational zero test cannot be used to find irrational roots as well as rational roots.
Yes.
Not necessarily. The cube roots of 4, 6 and 9 are all irrational (and different). But their product is 6, not just rational, but an integer.
No. The square roots 8 are irrational, as are the square roots of most even numbers.
An algebraic number is one which is a root of a polynomial equation with rational coefficients. All rational numbers are algebraic numbers. Irrational numbers such as square roots, cube roots, surds etc are algebraic but there are others that are not. A transcendental number is such a number: an irrational number that is not an algebraic number. pi and e (the base of the exponential function) are both transcendental.
They are 0.5 : it is a triple root.