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How long is the diagonal of a rectangle with the length of 30 yd and the width of 30 yd?
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
What is length of diagonal line in a rectangle 34 feet by 30 feet?
The diagonal line forms two triangles, each with one side 34 feet long and one side 30 feet long. Use Pythagorean Theorem to find the length of the diagonal line which is the hypotenuse of the triangles. a^2 + b^2 = c^2 Where a and b are the sides of the triangle and c is the hypotenuse. (34)^2 + (30)^2 = c^2 1156 + 900 = c^2 2056 = c^2 45.34 = c So, the diagonal line is 45.34 feet.
How long is the diagonal of a 30 ft x 50 ft rectangle?
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
What is the area of a rectangle 6 feet long and 5 feet wide?
The area of a rectangle is calculated by multiplying its length by its width. In this case, the rectangle is 6 feet long and 5 feet wide, so the area would be 6 feet x 5 feet = 30 square feet.
If a rectangle is 45 feet long and 30 yards wide what is the perimeter in feet?
270 feet.
