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Q: Can You Solve for x. (5x) - (2(x-3)) 0?
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What is 2x3 plus 11x equals 6x?

your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i


Solve 2x3 plus 5x-5?

2 x 3 = 65 x -5 = -256 + -25 = -19


How do you find value of x of 5x-8?

you just equal that equation to 0, then you solve for x 5x-8=0 5x=8 x=8/5


How do you solve the quadratic equation 7x2-5x equals 0 by factoring?

if the x in "7x2" is variable x, then 7x(2)-5x=0 14x-5x=0 9x=0 x=0 if the x in "7x2" is a symbol for multiplication, then 7(2)-5x=0 14-5x=0 -5x= -14 5x=14 x= 14/5 x= 2 4/5 or, to factor it out... x(14-5)=0 x(9)=0 9x=0


Solve sin 5x plus sin x equals 0?

Assuming the angles are expressed in radians:sin(5x) + sin(x) = 0∴ sin(5x) = -sin(x)∴ 5x = x + π∴ x = π/4On the other hand, if your angles are in degrees, then the answer would be:sin(5x) + sin(x) = 0∴ sin(5x) = -sin(x)∴ 5x = x + 180∴ x = 180°/4∴ x = 45°


X squared plus 5x?

1. If the question is only to factor this expression:x^2 + 5x = x(x + 5)2. If the question is to solve the equation x^2 + 5x = 0:x^2 + 5x = 0 factor it;x(x + 5) = 0x = 0 orx + 5 =0 subtract 5 to both sides;x = - 5


What is 2x cubed plus x squared minus 13x plus 6 divided by x minus 2 giving reasons why your answer is correct?

Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.


How do you solve x2 5x 4 in a descending order?

If you mean: x2+5x+4 = 0 then the solutions are x = -1 and x = -4


How do you solve 5xsquared - 2x equals 0?

5x2-2x = 0 x(5x-2) = 0 Therefore: x = 0 or x = 2/5


How do you solve x squared minus 5x minus 36?

x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.


What is the x-intercept of the line 5x-2y equals 10?

X intercept is where it intersects the X-axis, which is where y = 0. So set y=0 in the equation, and solve for x. 5x - 2(0) = 10 --> 5x = 10 --> x = 2. So the point (2,0) is where the x-intercept is.


What is the xintercept for 5x - 4y equals 18?

To find the x-intercept for 5x - 4y = 18, plug in a 0 for the y value and solve for x. 5x - 4(0) = 18 5x = 18 x = 18/5 or 3.6 The line will hit the x-axis at (3.6,0)