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How do you find the perimeter of a rectangle in feet?
you add the l+l and the w+w so it look like this l+l+w+w+
What is the length and width of a rectangular lot if its perimeter is 88m and its area is 480m2?
The equation for the perimeter is: 2(L + W) = 88m ie L + W = 44m So that L = 44 - W Then area = L*W = 480 m2 is equivalents to (44 - W)*W = 480 Or W2 - 44W + 480 = 0 which gives W = 20 or W = 24 if W = 20 then L = 24 and if W = 24 the L = 20 However, since conventionally, L>W, L = 24m, W = 20m
What is the dimension of a rectangular garden with a perimeter of 130?
Let W be any number between 0 and 32.5 (both end points excluded.) Let L = 65 - W Then the garden with length L and width W will have a perimeter of 2*(L+W) = 2*(65 - W + W) = 2*65 = 130 Since W can take an infinite number of values, there are an infinite number of possible solutions.
How would you find the area and perimiter of a rectangle?
If the length and width are denoted by l and w, then area = lw ( the product of l time w) and perimeter = 2(l+w) that is, twice the sum of l and w.
What is W equals P half minus L solve for L?
L = P/2 - W.
How do you find the perimeter of a rectangle in feet?
you add the l+l and the w+w so it look like this l+l+w+w+
If a carpet has an area of 48 square meters and the perimeter is 32 square meters what is the length and width?
Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4 Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4
What is the perimeter of a rectangle od side legh l and width w?
The perimeter is [ L + W + L + W ], or [ 2L + 2W ], or 2(L + W) .
What is the length and width of a rectangular lot if its perimeter is 88m and its area is 480m2?
The equation for the perimeter is: 2(L + W) = 88m ie L + W = 44m So that L = 44 - W Then area = L*W = 480 m2 is equivalents to (44 - W)*W = 480 Or W2 - 44W + 480 = 0 which gives W = 20 or W = 24 if W = 20 then L = 24 and if W = 24 the L = 20 However, since conventionally, L>W, L = 24m, W = 20m
What are the dimensions of a rectangle which has an area of 72cm2 and perimeter of 44 cm?
Suppose the Length and Width are L and W. Then Perimeter: 2(L + W) = 44 so that L + W = 22 and W = 22 - L and Area: L*W = 72 so that L*(22 - L) = 72 ie L2 - 22L + 72 = 0 (L - 4) (L - 18) = 0 Then L = 4 giving W = 18 or L = 18 giving W = 4 Since L > W (by convension), the answer is L =18 cm and W = 4 cm Substituting the
Area formula of a rectangle?
A = Area l = length w = width A = (l)(w) Ex: L = 5 in. W = 2 in. A = ? A = l(w) A = 5(2) A = 10 in2
A rectangle has an area of 120 square cm What are the possible dimensions?
w=3 L=40 ; w=4 L=30 ; w=2 L=60 ; w=6 L=20 ; w=5 L=24 ; etc.
What is the dimension of a rectangular garden with a perimeter of 130?
Let W be any number between 0 and 32.5 (both end points excluded.) Let L = 65 - W Then the garden with length L and width W will have a perimeter of 2*(L+W) = 2*(65 - W + W) = 2*65 = 130 Since W can take an infinite number of values, there are an infinite number of possible solutions.
A rectangle has perimeter of 20m Express the area of the rectangle as a function of the length of one of its sides?
In a rectangle: P = 2(L + W) and A = LW P = 2(L + W) (replace P with 20) 20 = 2(L + W) (solve for L; divide by 2 to both sides) 10 = L + W (subtract W to both sides ) 10 - W = L A = LW (substitute 10 - W for L) A = (10 - W)W A = 10W - W2
How much length and width is equal to 4046.8 square meters?
If the area is a square, then L = W = 63.61 metres (approx). If the area is a rectangle, then the answer is indeterminate. For example, L = 64, W = 63.23 or L = 64.1 W = 63.13 or L = 64.2 W = 63.03 etc or L = 640 W = 6.323 or L = 6400 W = 0.6323 or L = 64000, W = 0.06323 etc there are an infinity of options.
How would you find the area and perimiter of a rectangle?
If the length and width are denoted by l and w, then area = lw ( the product of l time w) and perimeter = 2(l+w) that is, twice the sum of l and w.
The perimeter of a rectangle is 14 feet and the area is 12 square feet What is the width of the rectangle?
Suppose the length is L feet and the width is W feet. Then, Perimeter = 14 => 2*(L+W) = 14 or L+W=7 Also, Area = 12 => L*W=12 You could try trial and error to solve these two equations and in this particular case you will get to the answer quite quickly but for a more general method: L+W=7 => W=7-L Substituting in the second equation, L*(7-L)=12 or L^2 - 7L + 12 = 0 L^2 - 3L - 4L + 12 = 0 (L-3)*(L-4) = 0 so L=3 or L=4 But L>W and L+W = 7 so L > 3.5 so L= 4 => W=3 feet
