102 ÷ 3 = 34
3 + 3 + 3/3 = 7
4=4(3s) 4=12s s= 1/3
0.1288
You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6
33 + (3/3)
102 ÷ 3 = 34
3 + 3 + 3/3 = 7
4=4(3s) 4=12s s= 1/3
5s - 3 = 3s - 92s = -6s = -3
0.1288
4s 3p 3s 2p 1s This is probably one of the easiest chemistry problems in the book, you should probably look it up.
(3+3) / .3
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6
It could be: 33-(3+3) = 21
3 plus 3 plus 3 over 3So 3 + 3 =6. 3 over 3 is 1. 6 + 1 = 7