Since I know I need x2 and everything is positive and added, I start like this:
(x + )(x + )
Then I look for two numbers that will add to 8 and multiply to 12.
(x + 6)(x + 2)
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x2 + 8x + 15 = (x + 3) (x + 5).
x2 + 8x = x(x+8)
x + 4
x2+8x+9 = -7 x2+8x+9+7 = 0 x2+8x+16 = 0 (x+4)(x+4) = 0 Therefore: x = -4 and also x = -4 (they both have equal roots)
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3