That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
x = 0.125 ( BC - 7 )
a+bc/2+c=10
The square root of 149 (7 squared plus 10 squared equals 149).
bc equals st multiplied by the scale factor.
21.4
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
x = 0.125 ( BC - 7 )
\3
2
50
let abc be the triangle with base bc. Consider it is equilateral triangle.. Now draw ad perpendicular to bc. Now ad equalls dc. Now tan 60 degree equalls ad/dc. With value of tan 60 and ad we can find dc. There fore bc equalls 2 * dc
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
25
a+bc/2+c=10
12
The square root of 149 (7 squared plus 10 squared equals 149).