0
5ex+2?
d/dx(u+v)=du/dx+dv/dx
d/dx(5ex+2)=d/dx(5ex)+d/dx(2)
-The derivative of 5ex is:
d/dx(cu)=c*du/dx where c is a constant.
d/dx(5ex)=5*d/dx(ex)
-The derivative of 2 is 0 because it is a constant.
d/dx(5ex+2)=(5*d/dx(ex))+(0)
d/dx(5ex+2)=5*d/dx(ex)
-The derivative of ex is:
d/dx(eu)=eu*d/dx(u)
d/dx(ex)=ex*d/dx(x)
d/dx(5ex+2)=5*(ex*d/dx(x))
-The derivative of x is:
d/dx(xn)=nxn-1
d/dx(x)=1*x1-1
d/dx(x)=1*x0
d/dx(x)=1*(1)
d/dx(x)=1
d/dx(5ex+2)=5*(ex*1)
d/dx(5ex+2)=5*(ex)
d/dx(5ex+2)=5ex
5ex+2?
d/dx(cu)=c*du/dx where c is a constant.
d/dx(5ex+2)=5*d/dx(ex+2)
-The derivative of ex+2 is:
d/dx(eu)=eu*d/dx(u)
d/dx(ex+2)=ex+2*d/dx(x+2)
d/dx(5ex+2)=5*(ex+2*d/dx(x+2))
-The derivative of x+2 is:
d/dx(u+v)=du/dx+dv/dx
d/dx(x+2)=d/dx(x)+d/dx(2)
d/dx(5ex+2)=5*[ex+2*(d/dx(x)+d/dx(2))]
-The derivative of x is:
d/dx(xn)=nxn-1
d/dx(x)=1*x1-1
d/dx(x)=1*x0
d/dx(x)=1*(1)
d/dx(x)=1
-The derivative of 2 is 0 because it is a constant.
d/dx(5ex+2)=5*[ex+2*(1+0)]
d/dx(5ex+2)=5*[ex+2*(1)]
d/dx(5ex+2)=5*[ex+2]
d/dx(5ex+2)=5ex+2
Still curious? Ask our experts.
Chat with our AI personalities
Taiga
Devin
LaoAdd your answer:
Earn +20 pts
What is the derivative of 2x plus 3?
2
Derivative 3 plus 2 x - 4 x2?
y = 3 + 2x - 4x^(2) dy/dx = 2 - 8x ( The derivative).
What is the derivative of 1 divided by 1 plus x?
2
What is the derivative of x plus root x?
Derivative of x = 1, and since sqrt(x) = x^(1/2), derivative of x^(1/2) = (1/2)*(x^(-1/2))Add these two terms together and derivative = 1 + 1/(2*sqrt(x))
How do you derivative x plus y - 1 equals ln x2 plus y2?
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
