0
5ex+2?
d/dx(u+v)=du/dx+dv/dx
d/dx(5ex+2)=d/dx(5ex)+d/dx(2)
-The derivative of 5ex is:
d/dx(cu)=c*du/dx where c is a constant.
d/dx(5ex)=5*d/dx(ex)
-The derivative of 2 is 0 because it is a constant.
d/dx(5ex+2)=(5*d/dx(ex))+(0)
d/dx(5ex+2)=5*d/dx(ex)
-The derivative of ex is:
d/dx(eu)=eu*d/dx(u)
d/dx(ex)=ex*d/dx(x)
d/dx(5ex+2)=5*(ex*d/dx(x))
-The derivative of x is:
d/dx(xn)=nxn-1
d/dx(x)=1*x1-1
d/dx(x)=1*x0
d/dx(x)=1*(1)
d/dx(x)=1
d/dx(5ex+2)=5*(ex*1)
d/dx(5ex+2)=5*(ex)
d/dx(5ex+2)=5ex
5ex+2?
d/dx(cu)=c*du/dx where c is a constant.
d/dx(5ex+2)=5*d/dx(ex+2)
-The derivative of ex+2 is:
d/dx(eu)=eu*d/dx(u)
d/dx(ex+2)=ex+2*d/dx(x+2)
d/dx(5ex+2)=5*(ex+2*d/dx(x+2))
-The derivative of x+2 is:
d/dx(u+v)=du/dx+dv/dx
d/dx(x+2)=d/dx(x)+d/dx(2)
d/dx(5ex+2)=5*[ex+2*(d/dx(x)+d/dx(2))]
-The derivative of x is:
d/dx(xn)=nxn-1
d/dx(x)=1*x1-1
d/dx(x)=1*x0
d/dx(x)=1*(1)
d/dx(x)=1
-The derivative of 2 is 0 because it is a constant.
d/dx(5ex+2)=5*[ex+2*(1+0)]
d/dx(5ex+2)=5*[ex+2*(1)]
d/dx(5ex+2)=5*[ex+2]
d/dx(5ex+2)=5ex+2
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