yes
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
The answer is indeterminate. For example, if the equation is of the form x2 - 2ax + y2 - 2by = 25, all that can be said of the radius of the circle is that it is greater than 5.
Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.
There are different standard forms for different things. There is a standard form for scientific notation. There is a standard form for the equation of a line, circle, ellipse, hyperbola and so on.
yes
9
The Pythagorean theorem is used to develop the equation of the circle. This is because a triangle can be drawn with the radius and any other adjacent line in the circle.
Area of a circle = pi*radius squared Circumference of a circle = 2*pi*radius or diameter*pi
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
(x - A)2 + (y - B)2 = R2 The center of the circle is the point (A, B) . The circle's radius is ' R '.
If a = b then it is a circle; otherwise it is an ellipse.
There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.
The answer is indeterminate. For example, if the equation is of the form x2 - 2ax + y2 - 2by = 25, all that can be said of the radius of the circle is that it is greater than 5.
I'm happy to help you check! Please provide me with the equation you are referencing so I can assist you further.
Roughly 66.5° is the latitude of every point on the Arctic Circle.