Lots! As long as half the length of the base times the height is 20...
If you draw a diagonal in a rectangle you get two equal triangles, each half the area of the rectangle. Area of rectangle is base x height, so half of that is ½ x base x height. QED
Yes. Draw a triangle, then draw line through the top vertex that's parallel to the base. Now draw another point anywhere on that line, and draw sides that meet the edges of the base and the new point you've drawn. No matter where that point is on your line, you haven't changed the height, and you haven't changed the base, but the angles of the triangle have changed. Therefore, the two aren't congruent.
area =1/2 base length x height
No, a triangles area is calculated from base x height / 2
Lots! As long as half the length of the base times the height is 20...
If you draw a diagonal in a rectangle you get two equal triangles, each half the area of the rectangle. Area of rectangle is base x height, so half of that is ½ x base x height. QED
Yes. Draw a triangle, then draw line through the top vertex that's parallel to the base. Now draw another point anywhere on that line, and draw sides that meet the edges of the base and the new point you've drawn. No matter where that point is on your line, you haven't changed the height, and you haven't changed the base, but the angles of the triangle have changed. Therefore, the two aren't congruent.
Only if the two triangles have the same base and height then they have the same area, because an area of a triangle OS the base times the height divided by two.
area =1/2 base length x height
You draw a square for the base of the pyramid and then you draw triangles for the 4 faces. Hope this helps!
No, a triangles area is calculated from base x height / 2
False. The equation for area of a triangle is 1/2 base x height. The height and the base would have to be the same for two triangles to have the same area.
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
Not necessarily. You find the area of a triangle with the formula 1/2*base*height=Area. Imagine two triangles, one with 3 inches for both the base and height, and one with 4.5 inches for the height and 2 inches for the base. Both of these triangles will have 9 sq. in. for their areas, but they are not congruent.
half of the base multipled by the height
Half of the base times height.