x2 + 9 = (x + 3i)(x - 3i) The answer is based on a knowledge of imaginary and complex numbers where i2 = -1
x + 4
x2 + 5x - 120 can not be factored.
x2 + 8x + 15 = (x + 3) (x + 5).
(x2 plus 40) (x minus 1)
x2 + 12x + 32 = (x + 8)(x + 4)
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
x2-8x+15 = (x-3)(x-5)
x2 + 9 = (x + 3i)(x - 3i) The answer is based on a knowledge of imaginary and complex numbers where i2 = -1
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x + 4
x2(x3 + 1) is the best you can do there.
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
You can't factor it
That does not factor neatly.
Not factorable
1