Start with an integer x. Since a consecutive integer will simply be 1 more than its neighbor, you can say that the three numbers you're trying to find are x, x + 1, and x + 2. So construct your equation using these three numbers as your consecutive integers:
4(x + (x + 1)) = 6(x + 2)
4(2x + 1) = 6(x + 2)
8x + 4 = 6x + 12
2x = 8
x = 4
Therefore, the three consecutive integers are 4, 5 (4 + 1), and 6 (4 + 2).
18, 20 and 22
Their sum is 99.
-1, 1 and 3
The integers would begin with 10.
The 3 consecutive odd positive integers are 7, 9 and 11.
9,10,11,12
10-11-12
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
18, 20 and 22
Their sum is 99.
-1, 1 and 3
1, 2 and 3 -1, -2, and -3 6 or -6
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
greater
The integers would begin with 10.
The sum of three consecutive integers is -72
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.