5
The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
Equation: y = 2x+10 Point: (2, 4) Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 Both equations intersect at: (-2, 6) Using distance formula: (2, 4) to (-2, 6) = 2 times square root of 5
(I am going to assume you are higher or in grade 9 math) So use the y=mx + b Use the negative reciprocal of the "m"(slope) part. Do this by simply flipping the fraction. This slope will be perpendicular to the original formula.
General formula
5
The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
Equation: y = 2x+10 Point: (2, 4) Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 Both equations intersect at: (-2, 6) Using distance formula: (2, 4) to (-2, 6) = 2 times square root of 5
(I am going to assume you are higher or in grade 9 math) So use the y=mx + b Use the negative reciprocal of the "m"(slope) part. Do this by simply flipping the fraction. This slope will be perpendicular to the original formula.
it is the slope formula in the equation it is the slope formula in the equation
Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula
Known equation: y = 2x+10 Perpendicular equation through point (2, 4): 2y = -x+10 Both equations intersect at: (-2, 6) Perpendicular distance from (2, 4) to (-2, 6) is 2 times square root of 5 by using the distance formula
If you think to magnetite and to a chemical formula (not equation) this formula is Fe3O4.
Area of a triangle = 0.5*base*perpendicular height Area of a parallelogram = base*perpendicular height
Line equation: 2x-y-5 = 0 => y = 2x-5 Perpendicular slope: -1/2 Perpendicular equation: y--2 = -1/2(x-2) => x+2y = 0 Both equations intersect at: (2, -1) Using distance formula from (4, -2) to (2, -1) = square root of 5