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Find the equation of the line using the point-slope formula. Write the final equation using the slope-intercept form. perpendicular to 3y x and minus 4 and passes through the point (-21)?
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What equation has a graph perpendicular to y equals 2x-3?
5
How does midpoint and distance formula fit into the big picture of math?
The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.
What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
Give the equation of a line that is perpendicular to a line?
(I am going to assume you are higher or in grade 9 math) So use the y=mx + b Use the negative reciprocal of the "m"(slope) part. Do this by simply flipping the fraction. This slope will be perpendicular to the original formula.
What is the perpendicular distance from the point of 2 4 to the equation y equals 2x plus 10 on the Cartesian plane showing work?
Equation: y = 2x+10 Point: (2, 4) Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 Both equations intersect at: (-2, 6) Using distance formula: (2, 4) to (-2, 6) = 2 times square root of 5
Which equation represents a line that passes through the point (5, 5) and is perpendicular to the line x + 2y = 10?
General formula
What equation has a graph perpendicular to y equals 2x-3?
5
How does midpoint and distance formula fit into the big picture of math?
The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.
What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
Give the equation of a line that is perpendicular to a line?
(I am going to assume you are higher or in grade 9 math) So use the y=mx + b Use the negative reciprocal of the "m"(slope) part. Do this by simply flipping the fraction. This slope will be perpendicular to the original formula.
What is the perpendicular distance from the point of 2 4 to the equation y equals 2x plus 10 on the Cartesian plane showing work?
Equation: y = 2x+10 Point: (2, 4) Perpendicular slope: -1/2 Perpendicular equation: y-4 = -1/2(x-2) => 2y = -x+10 Both equations intersect at: (-2, 6) Using distance formula: (2, 4) to (-2, 6) = 2 times square root of 5
What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane?
Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula
What is a-bxc in math?
it is the slope formula in the equation it is the slope formula in the equation
What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10?
Known equation: y = 2x+10 Perpendicular equation through point (2, 4): 2y = -x+10 Both equations intersect at: (-2, 6) Perpendicular distance from (2, 4) to (-2, 6) is 2 times square root of 5 by using the distance formula
What is the chemical equation for?
If you think to magnetite and to a chemical formula (not equation) this formula is Fe3O4.
How is the formula for the area of a triangle related to the formula for an area of a parallelogram?
Area of a triangle = 0.5*base*perpendicular height Area of a parallelogram = base*perpendicular height
What is the perpendicular diatance from the point 4 -2 to the line 2x -y -5 equals 0?
Line equation: 2x-y-5 = 0 => y = 2x-5 Perpendicular slope: -1/2 Perpendicular equation: y--2 = -1/2(x-2) => x+2y = 0 Both equations intersect at: (2, -1) Using distance formula from (4, -2) to (2, -1) = square root of 5
