Suppose the three integers are 2x-2, 2x and 2x+2 for some integer x.
Then 4*(2x-2) - (2x+2) = 2*2x + 6
or 8x - 8 - 2x - 2 = 4x + 6
=> 6x - 10 = 4x + 6 => 2x = 16 so that x = 8.
So the numbers are 14, 16 and 18.
The smallest is 121.
Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.
consecutive integers
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
The smallest is 121.
59,61,63,65 It is 59
Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.
consecutive integers
If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer. Let the smallest integer be x, then the others are x + 2 and x+ 4. Therefore 4x - (x + 4) = 2 (x + 2 ) + 4 Expanding, we get 4x -x -4 = 2x + 4 + 4 Gathering terms: x = 12 Thus the three integers are 12, 14 and 16.
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
"Consecutive" integers are integers that have no other integer between them.
The sum of three consecutive integers is -72
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
1 is the smallest positive integer. But if you include negative integers, there is no smallest.
Let x equal the smallest integer. The sum will be 3x + 6