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There are several infinite series. To find PI to x digits, evaluate each term to x+2 digits until the value is 0. Then round to x digits.
1,944 = 1296 x 1.5
The answer depends on what information you have been provided with.
That depends under what context v is used because its can have infinite values.
There is no simple answer. There are simple formulae for simple sequences such as arithmetic or geometric progressions; there are less simple solutions arising from Taylor or Maclaurin series. But for the majority of sequences there are no solutions.
There are several infinite series. To find PI to x digits, evaluate each term to x+2 digits until the value is 0. Then round to x digits.
1,944 = 1296 x 1.5
160... I think. The series is 80+40+20+10+5+2.5+............ (Given the series is infinite it never ends but it gets pretty close to 160) = 159.99999999... ad infinitum [For future reference... series like this are basically equal to 2*the highest value e.g. 2*80=160]
It is 58465.
The answer depends on what information you have been provided with.
Divide any term in the sequence by the previous term. That is the common ratio of a geometric series. If the series is defined in the form of a recurrence relationship, it is even simpler. For a geometric series with common ratio r, the recurrence relation is Un+1 = r*Un for n = 1, 2, 3, ...
1/8
An infinite geometric series can be summed only if the common ratio has an absolute value less than 1. Suppose the sum to n terms is S(n). That is, S(n) = a + ar + ar2 + ... + arn-1 Multipying through by the common ratio, r, gives r*S(n) = ar + ar2 + ar3 + ... + arn Subtracting the second equation from the first, S(n) - r*S(n) = a - arn (1 - r)*S(n) = a*(1 - rn) Dividing by (1 - r), S(n) = (1 - rn)/(1 - r) Now, since |r| < 1, rn tends to 0 as n tends to infinity and so S(n) tends to 1/(1 - r) or, the infinite sum is 1/(1 - r)
The Nth partial sum is the sum of the first n terms in an infinite series.
That depends under what context v is used because its can have infinite values.
For a number to be rational you need to be able to write it as a fraction. To answer your question, it must repeat as a decimal or else terminate which can be thought of as repeating zeroes. Further, every repeating decimal can be written as a fraction and you can find the fraction by using the formula for the sum of an infinite geometric series.
There is no simple answer. There are simple formulae for simple sequences such as arithmetic or geometric progressions; there are less simple solutions arising from Taylor or Maclaurin series. But for the majority of sequences there are no solutions.