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How do you simplify bracket 1 plus tan theta bracket bracket 5 sin theta -2 bracket equals 0?
(in a past paper it asks u to solve this for -180</=theta<180, so I have solved it) Tan theta =-1, so theta = -45. Use CAST diagram to find other values of theta for -180</=theta<180: Theta (in terms of tan) = -ve, other value is in either S or C. But because of boundaries value can only be in S. So other value= 180-45=135. Do the same for sin. Sin theta=2/5 so theta=23.6 CAST diagram, other value in S because theta (in terms of sin)=+ve. So other value=180-23.6=156.4.
What is value of tan15' tan195'?
To find the value of (\tan(15^\circ) \tan(195^\circ)), we can use the identity (\tan(195^\circ) = \tan(15^\circ + 180^\circ) = \tan(15^\circ)). Thus, (\tan(195^\circ) = \tan(15^\circ)). Consequently, (\tan(15^\circ) \tan(195^\circ) = \tan(15^\circ) \tan(15^\circ) = \tan^2(15^\circ)). The exact value of (\tan^2(15^\circ)) can be computed, but it is important to note that it will yield a positive value.
What is the exact value of tan 195?
The exact value of (\tan 195^\circ) can be found using the tangent addition formula. Since (195^\circ) is in the third quadrant, where tangent is positive, we can express it as (\tan(180^\circ + 15^\circ)). This gives us (\tan 195^\circ = \tan 15^\circ), which is (\frac{\sin 15^\circ}{\cos 15^\circ}). Using the known values, (\tan 15^\circ = 2 - \sqrt{3}). Therefore, (\tan 195^\circ = 2 - \sqrt{3}).
What is periodical in reference to math?
It is used when a function takes the same values after some fixed interval, and multiples of that interval. For example, tan(x) = tax(x + 180) = tan(x + 360) = tan(x + n*180) for all integer values of n. So tan is said to be periodic, with period 180 degrees (or π radians).
Tan 9 plus tan 81 -tan 27-tan 63?
tan(9) + tan(81) - tan(27) - tan(63) = 4
How do you find the value of tan 135?
tan(135) = -tan(180-135) = -tan(45) = -1
Tan 180 plus a?
Tangent repeats every 180 degrees, so Tan(180 + a) = tan(a). This site has several useful identities.http://www.mathwords.com/t/trig_identities.htm
Find the value of a if tan 3a is equal to sin cos 45 plus sin 30?
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.
How do you simplify bracket 1 plus tan theta bracket bracket 5 sin theta -2 bracket equals 0?
(in a past paper it asks u to solve this for -180</=theta<180, so I have solved it) Tan theta =-1, so theta = -45. Use CAST diagram to find other values of theta for -180</=theta<180: Theta (in terms of tan) = -ve, other value is in either S or C. But because of boundaries value can only be in S. So other value= 180-45=135. Do the same for sin. Sin theta=2/5 so theta=23.6 CAST diagram, other value in S because theta (in terms of sin)=+ve. So other value=180-23.6=156.4.
What is value of tan15' tan195'?
To find the value of (\tan(15^\circ) \tan(195^\circ)), we can use the identity (\tan(195^\circ) = \tan(15^\circ + 180^\circ) = \tan(15^\circ)). Thus, (\tan(195^\circ) = \tan(15^\circ)). Consequently, (\tan(15^\circ) \tan(195^\circ) = \tan(15^\circ) \tan(15^\circ) = \tan^2(15^\circ)). The exact value of (\tan^2(15^\circ)) can be computed, but it is important to note that it will yield a positive value.
If tansqtheta plus 5tantheta0 find the value of tantheta plus cottheta?
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
By using trigonometric identities find the value of sin A if tan A a half?
The value of tan A is not clear from the question.However, sin A = sqrt[tan^2 A /(tan^2 A + 1)]
How you find six trig functions of 180 degree?
To find the six trigonometric functions of 180 degrees, we can use the unit circle. At 180 degrees, the coordinates of the point on the unit circle are (-1, 0). Thus, the sine function (sin) is 0, the cosine function (cos) is -1, and the tangent function (tan) is 0. Consequently, the values for the six trig functions are: sin(180°) = 0, cos(180°) = -1, tan(180°) = 0, csc(180°) is undefined, sec(180°) = -1, and cot(180°) is undefined.
How do you find the period of tangent function?
You find the smallest positive value y such that tan(x + y) = tan(x) for all x.
How do you calculate trigonometric ratios of obtuse angles?
If ø is an obtuse angle then (180 - ø) is an acute angle and: sin ø = sin (180 - ø) cos ø = -cos (180 - ø) tan ø = -tan (180 - ø)
What is the half angle formula to find the exact value for tan 165?
tan u/2 = sin u/1+cos u
What is the exact value of tan 195?
The exact value of (\tan 195^\circ) can be found using the tangent addition formula. Since (195^\circ) is in the third quadrant, where tangent is positive, we can express it as (\tan(180^\circ + 15^\circ)). This gives us (\tan 195^\circ = \tan 15^\circ), which is (\frac{\sin 15^\circ}{\cos 15^\circ}). Using the known values, (\tan 15^\circ = 2 - \sqrt{3}). Therefore, (\tan 195^\circ = 2 - \sqrt{3}).
