a, ar, ar^2 and ar^3 where a and r are constants.
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The first four terms are 3 9 27 81 and 729 is the 6th term.
9, 10, 11 and 12
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
1, 16, 81, 256 14641 is the 11th term.
Question is not very clear about the context of word 'sequence' here. If I am to select 4 numbers out of four and arrange them in order then there are 4!*8C4 = 1680 different sequences possible. If the word sequence refers to some arithmetic sequence or geometric sequence, then counting is going to change for sure.