The first four terms are 3 9 27 81 and 729 is the 6th term.
9, 10, 11 and 12
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
1, 16, 81, 256 14641 is the 11th term.
Question is not very clear about the context of word 'sequence' here. If I am to select 4 numbers out of four and arrange them in order then there are 4!*8C4 = 1680 different sequences possible. If the word sequence refers to some arithmetic sequence or geometric sequence, then counting is going to change for sure.
5
The first four terms are 3 9 27 81 and 729 is the 6th term.
2
6
9, 10, 11 and 12
29
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
We need help with answering this question.
1, 16, 81, 256 14641 is the 11th term.
Question is not very clear about the context of word 'sequence' here. If I am to select 4 numbers out of four and arrange them in order then there are 4!*8C4 = 1680 different sequences possible. If the word sequence refers to some arithmetic sequence or geometric sequence, then counting is going to change for sure.
Assuming the recursive definition is tn = 2*tn-1 t1 = 3 t2 = 2*t1 = 2*3 = 6 t3 = 2*t2 = 2*6 = 12 t4 = 2*t3 = 2*12 = 24
200, 20, 2, 0.2 Here you have 4 terms. Add them together, and you find the sum of these four terms. If you need to find the sum of some other terms, i.e 8 terms, then you can use the formula Sn = [a1(r^n - 1/(r - 1) where n = 8, a1 = 200, and r = 1/10.