You need to replace all the variables with the numbers specifed from above. When a letter and a number are placed side-by-side like you have in your equation that means to multiply. So, when you replace all the variabls with the correct numbers you have:
=4(8)-5(-3)-2(1)
So, when that is multiplied out you get:
=32+15-2
You may see the I added a plus sign in front of the fifteen, when two negative numbers are multiplied the negative numbers become a positive number. When added together you get 45.
Pr(3H given >= 2H) = Pr(3H and >= 2H)/Pr(>=2H) = Pr(3H)/Pr(>=2H) = (1/4)/(11/16) = 4/11.
6h 8min
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
Yes, provided p = perimeter, b= breadth and h = height.
No because it equals zero.
76-2*6=444
Factor 2h−2 2h−2 =2(h−1) Answer: 2(h−1)
3h-5h + 11 = 17 is ------2h + 11 = 17- 11 -11____________-2h = 6___ ___-2 -2h = -3 (This is the answer.)
Pr(3H given >= 2H) = Pr(3H and >= 2H)/Pr(>=2H) = Pr(3H)/Pr(>=2H) = (1/4)/(11/16) = 4/11.
g = 2h/t2
6h 8min
When h=10, 2h-9 = 2(10)-9 = 20-9 = 11 .
D=2h h=4000ft D=2(4000 ft) D=8000 ft
2h + 2h + 2h = 6h
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
First set up the equation: 2h+10=40 Then get the variable alone by subtracting 10 from each side: 2h=30 And continue by dividing both sides by two 2h=30 ______ 2 2 h=15 So your answer is h=15