Rearrange: x2 - 10x + 25 = 0ie (x - 5)(x - 5) = 0x = 5Check: x2 = 25; 10x - 25 = 50 - 25 = 25. Job done
x^2 + 10x + 16 = (x + 8)(x + 2)
That depends what the value of x is.
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
Do you mean, what is the value of 0.55555...? Call it x. Then 10x = 5.5555... Now subtract x from 10x 10x - x = 5.55555... - 0.55555... 9x = 5 x = 5/9 Done.
(x + 5)(x + 5)
7
X3 + 10X2 + 25Xfactor out an XX(X2 + 10X + 25)factor inside parenthesesX(X + 5)(X + 5)X(X + 5)2=======X = 0X = - 5
Rearrange: x2 - 10x + 25 = 0ie (x - 5)(x - 5) = 0x = 5Check: x2 = 25; 10x - 25 = 50 - 25 = 25. Job done
( x^2 + 10x )^2 = ( x^2 + 10 x) ( x^2 + 10x ) = x^4 + 10x^3 + 10x^3 + 100x^2 = x^4 + 20x^3 + 100x^2 <----------------
x^2 + 10x + 16 = (x + 8)(x + 2)
x2 + 9x2 = 10x2
x2-10x-24 = (x+2)(x-12) when factored
2(5x + 7)(x - 5)
X2 + 10X - 13 = 17 add 13 to each side X2 + 10X = 30 halve the linear coefficient ( 10 ), square it and add it to both sides X2 + 10X + 25 = 30 + 25 factor on the left and gather terms on the right (X + 5)2 = 55 (X + 5)2 - 55 = 0 ---------------------------vertex form, (- 5, - 55 ), is the vertex -------------------------------------------[-------------------------------]
(x - 7)(x - 3)
Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5