answersLogoWhite

0

Whether tanning indoors or outdoors, it is important to be safe. You should NEVER overexpose yourself. It is the OVEREXPOSURE that can cause skin damage, not the exposure itself. If you are going to tan indoors, be sure to tan no more than every other day. Going every day can increase your chances of overexposure thus increasing your chances of skin damage. Don't spend more than the time recommended for you skin type in a tanning bed or too much time outside in the sun. The biggest problem among people these days is that if they pay for a 15 minute tanning bed, they expect to get 15 minutes even though they end up burning themselves. Tanning properly is a gradual process. Not an instant one.

A response to:

"you can go to a tanning bed but that can give you skin cancer"

For the record, tanning beds will not necessarily give you cancer. At least not any more than the sun. Most people who get skin cancer were most likely predisposed to get it anyway. (i.e., family history of cancer/skin cancer) Actually, most skin conditions that are diagnosed as "cancer" are really not. Only a very small percent are malignant. The rest are benign. Only the malignant ones can be considered cancer. The benefits that you get from tanning or sun exposure (such as increased Vitamin D production) are far greater than the risks.

User Avatar

Wiki User

13y ago

Still curious? Ask our experts.

Chat with our AI personalities

LaoLao
The path is yours to walk; I am only here to hold up a mirror.
Chat with Lao
ViviVivi
Your ride-or-die bestie who's seen you through every high and low.
Chat with Vivi
BlakeBlake
As your older brother, I've been where you are—maybe not exactly, but close enough.
Chat with Blake

Add your answer:

Earn +20 pts
Q: How can you get a tan?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Math & Arithmetic

Tan 9 plus tan 81 -tan 27-tan 63?

tan(9) + tan(81) - tan(27) - tan(63) = 4


If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?

tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).


What is tan 45?

tan 45 = 1


How do you solve for the exact value of tan 2 pi?

tan 2 pi = tan 360º = 0


How do you verify the identity of cos θ tan θ equals sin θ?

To show that (cos tan = sin) ??? Remember that tan = (sin/cos) When you substitute it for tan, cos tan = cos (sin/cos) = sin QED