x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
x3 - 4x2 + 5x - 20 = x2*(x - 4) + 5*(x - 4) = (x2 + 5)*(x - 4)
It is not possible to be sure about the answer because there is no sign before the linear term. If the polynomial is x3-4x2+x-4 then, the factors are (x-4) and (x2+1).
(x-2)(x+1)(x+5)
(x + 2)(x^2 + 2x + 3)
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
X3 - 4X2 - 45XX(X2 - 4X - 45)=============X is only common factor here.
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
x3 - 4x2 + 5x - 20 = x2*(x - 4) + 5*(x - 4) = (x2 + 5)*(x - 4)
It is not possible to be sure about the answer because there is no sign before the linear term. If the polynomial is x3-4x2+x-4 then, the factors are (x-4) and (x2+1).
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
(x - 2)(x + 4)(x - 6)
(x + 1)(x - 2)(x + 5)
(x-2)(x+1)(x+5)
4xx-18x+8 2(2xx-9x+4) 2(2xx-8x-1x+4) 2(2x(x-4)-1(x-4)) 2(2x-1)(x-4)
I am trying to read this right: (9 x 5) - x3 = ? or 9 x (5 - x3) = ? Which one is it?