The answer depends on the vertex of WHAT!
The vertex is at the origin of coordinates ... the point (0, 0).
0 vertex edges and 1 base.
(0, 0), of course. No linear term.
By inspection you should be able to see that this is a parabola with a vertex of this. (0, 0) There is no form for this function as there is no linear term.
The vertex is at the point (0, 4).
The vertex is at the origin of coordinates ... the point (0, 0).
A straight line has no vertex.
A point.
0 vertex edges and 1 base.
(0, 0) of course! No linear term! Review you vertex manipulation again.
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
(0, 0), of course. No linear term.
By inspection you should be able to see that this is a parabola with a vertex of this. (0, 0) There is no form for this function as there is no linear term.
The vertex is at the point (0, 4).
The vertex of a square can be represented by any of its corner points. For example, if a square is positioned with its bottom-left corner at the origin (0, 0) and has a side length of 1, the vertices would be (0, 0), (1, 0), (1, 1), and (0, 1). Therefore, one possible ordered pair representing a vertex of this square is (0, 0).
The number of Diagonals in one vertex of a Triangle is 0 (zero)..
Circle has no vertex, sides