The answer depends on the vertex of WHAT!
The vertex is at the origin of coordinates ... the point (0, 0).
0 vertex edges and 1 base.
(0, 0), of course. No linear term.
By inspection you should be able to see that this is a parabola with a vertex of this. (0, 0) There is no form for this function as there is no linear term.
The vertex of a square can be represented by any of its corner points. For example, if a square is positioned with its bottom-left corner at the origin (0, 0) and has a side length of 1, the vertices would be (0, 0), (1, 0), (1, 1), and (0, 1). Therefore, one possible ordered pair representing a vertex of this square is (0, 0).
The vertex is at the origin of coordinates ... the point (0, 0).
A straight line has no vertex.
A point.
0 vertex edges and 1 base.
(0, 0) of course! No linear term! Review you vertex manipulation again.
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
(0, 0), of course. No linear term.
By inspection you should be able to see that this is a parabola with a vertex of this. (0, 0) There is no form for this function as there is no linear term.
The vertex is at the point (0, 4).
The vertex of a square can be represented by any of its corner points. For example, if a square is positioned with its bottom-left corner at the origin (0, 0) and has a side length of 1, the vertices would be (0, 0), (1, 0), (1, 1), and (0, 1). Therefore, one possible ordered pair representing a vertex of this square is (0, 0).
The number of Diagonals in one vertex of a Triangle is 0 (zero)..
Circle has no vertex, sides