It is the y-axis, or the yz plane.
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It seems there may be a typo in your function notation. If you meant to express the function as ( f(x) = -2(x^3) + 5 ), you can find a point on the graph by choosing a value for ( x ). For example, if ( x = 0 ), then ( f(0) = -2(0^3) + 5 = 5 ). Thus, the point ( (0, 5) ) lies on the graph of the function.
It is the point of origin of the x and y axes of the graph
The lowest point is y = 0 when x = 0. All other values of y are greater than zero for any other value of x
x -3y = 0 -x = -x -3y=-x /-3 = /-3 y=1/3x Then solve y for different values of x, record the data , then graph the x and y position for each value of x. so for if x =1 y = 1/3 so one point on the graph is (1,1/3)
It can be casually called the x intercept, but it/they is/are the root(s) of the function represented by the graph