Q: How do I graph a point with a 0 as the x value?

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It is the point of origin of the x and y axes of the graph

The lowest point is y = 0 when x = 0. All other values of y are greater than zero for any other value of x

x -3y = 0 -x = -x -3y=-x /-3 = /-3 y=1/3x Then solve y for different values of x, record the data , then graph the x and y position for each value of x. so for if x =1 y = 1/3 so one point on the graph is (1,1/3)

It can be casually called the x intercept, but it/they is/are the root(s) of the function represented by the graph

A pair of numbers are usually (x,y) if u want to determine a point on a graph. Find the value for both x and y and then plot them on a graph

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It is the point of origin of the x and y axes of the graph

A point can represent a piece of data or an (x,y) value.

The lowest point is y = 0 when x = 0. All other values of y are greater than zero for any other value of x

x=0

point

It is the x intercept

If the discriminant = 0 then the graph touches the x axis at one point If the discriminant > 0 then the graph touches the x axis at two ponits If the discriminant < 0 then the graph does not meet the x axis

I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).

point

point

x -3y = 0 -x = -x -3y=-x /-3 = /-3 y=1/3x Then solve y for different values of x, record the data , then graph the x and y position for each value of x. so for if x =1 y = 1/3 so one point on the graph is (1,1/3)

It is the point of origin and its coordinates are at (0, 0)