The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.
The derivative of a curve is basically the slope of the curve. If we say, for example, that if y = 2x, the derivative is 2, that means that at any point the line has this slope. If we say that for the function y = x2, the derivative is 2x, that means that at any point "x", the slope is twice the value of "x".
Why: Because that's what the derivative means, the way it is defined - the slope of the curve at any point of the line.
If it is the equation for a line, then it can be rearranged into the format y = mx + b, where m is the slope of the line, and b is the point where the line intercepts the y-axis.If it is not for a straight line, then the slope is changing with x, and the derivative of the function would find the slope at a particular x.
To trace a curve using differential calculus, you use the fact that the first derivative of the function is the slope of the curve, and the second derivative is the slope of the first derivative. What this means is that the zeros (roots) of the first derivative give the extrema (max or min) or an inflection point of the function. Evaluating the first derivative function at either side of the zero will tell you whether it is a min/max or inflection point (i.e. if the first derivative is negative on the left of the zero and positive on the right, then the curve has a negative slope, then a min, then a positive slope). The second derivative will tell you if the curve is concave up or concave down by evaluating if the second derivative function is positive or negative before and after extrema.
Take the derivative of the function.
The derivative at any point in a curve is equal to the slope of the line tangent to the curve at that point. Doing it in terms of the actual expression of the curve, find the derivative of the curve, then plug the x-value of the point into the derivative to find the derivative at that point.
Yes, the derivative of an equation is the slope of a line tangent to the graph.
The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.
A derivative graph tracks the slope of a function.
Virtually everywhere; in fact the entire notion of the derivative of a function is based on slope. Both slope and derivative have uses in real life, e.g. your position, speed and acceleration can be calculated using either. Or, you could find the derivative of a logistics curve (a curve that models population growth), etc.
For example, if the slope at a certain point is 1.5, you can draw a line that goes through the specified point, with that slope. The line would represent the slope at that point. If you want to graph the slope at ALL POINTS, take the derivative of the function, and graph the derivative. The derivative shows the slope of a function at all points.
The smallest slope of a curve means the point at which the derivative (the slope) is minimal. So find the derivative first, then find the minimum value of this function. That means finding another derivative and setting it equal to zero to solve for x. Example with the curve y = x^3 - x^2 : The slope at any given point is given by the derivative, which is 3x^2 - 2x. To find the minimum value of this function, compute its derivative (which is 6x - 2) and set it equal to zero. Solve 6x - 2 = 0 for x and you'll find the answer. It's x = 1/3. This is the point at which the smallest slope occurs. The smallest slope ITSELF is the value of the first derivative at x = 1/3, so plug x = 1/3 into 3x^2 - 2x and you get -1/3. This method could also have found the LARGEST slope of the initial curve. So you have to make sure by computing the slope at another point (any other point). Take x = 0. There the slope is 0, which is bigger than -1/3. So the -1/3 value is indeed the SMALLEST slope.
The gradient of the tangents to the curve.
The smallest slope of a curve means the point at which the derivative (the slope) is minimal. So find the derivative first, then find the minimum value of this function. That means finding another derivative and setting it equal to zero to solve for x. Example with the curve y = x^3 - x^2 : The slope at any given point is given by the derivative, which is 3x^2 - 2x. To find the minimum value of this function, compute its derivative (which is 6x - 2) and set it equal to zero. Solve 6x - 2 = 0 for x and you'll find the answer. It's x = 1/3. This is the point at which the smallest slope occurs. The smallest slope ITSELF is the value of the first derivative at x = 1/3, so plug x = 1/3 into 3x^2 - 2x and you get -1/3. This method could also have found the LARGEST slope of the initial curve. So you have to make sure by computing the slope at another point (any other point). Take x = 0. There the slope is 0, which is bigger than -1/3. So the -1/3 value is indeed the SMALLEST slope.
The derivative of a curve is basically the slope of the curve. If we say, for example, that if y = 2x, the derivative is 2, that means that at any point the line has this slope. If we say that for the function y = x2, the derivative is 2x, that means that at any point "x", the slope is twice the value of "x".
there is only one way i know how to find the slope of a hyperbola and that is taking the implicit derivative of its equation, and solving for dy/dx but the answer is Slope= (x)*(b^2) / (y)*(a^2)