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Chain Rule:
let u=2x and y=tan(u)
du/dx = 2 and dy/du = sec^2(u)
dy/dx = du/dx x dy/du
multiply them together and replace u=2x into the equation..
therefore dy/dx = 2(sec^2(2x))
hope that helps.
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∙ 13y ago
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What does tangent 2 x plus 1 equal?
tan(2x) = 2tanx/(1 - tan2x) So tan(2x) +1 = 2tanx/(1 - tan2x) + 1 = 2tanx/(1 - tan2x) + (1 - tan2x)/(1 - tan2x) = (-tan2x + 2tanx + 1)/(1 - tan2x)
What is the range of y equals tan2x?
It depends on the domain of x.
How do you prove one - tan square x divided by one plus tan square xequal to cos two x?
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How do you simplify tanx plus 1 sqaured?
I assume you mean (tanx+1)^2 In which case, (tanx+1)^2=tan2x+2tanx+1
What is the period of y equals tan2x?
The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2
What does tangent 2 x plus 1 equal?
tan(2x) = 2tanx/(1 - tan2x) So tan(2x) +1 = 2tanx/(1 - tan2x) + 1 = 2tanx/(1 - tan2x) + (1 - tan2x)/(1 - tan2x) = (-tan2x + 2tanx + 1)/(1 - tan2x)
What is the vertical asymptotes for tan2x?
there is non its an infinite line.
What is the range of y equals tan2x?
It depends on the domain of x.
How do you prove one - tan square x divided by one plus tan square xequal to cos two x?
(1 - tan2x)/(1 + tan2x) = (1 - sin2x/cos2x)/(1 + sin2x/cos2x) = (cos2x - sin2x)/(cos2x + sin2x) = (cos2x - sin2x)/1 = (cos2x - sin2x) = cos(2x)
How do you differentiate tan2 x?
By using the chain rule: dy/dx = dy/du x du/dx With y = tan2x Let u = tan x Then: y = u2 du/dx = d/dx tan x = sec2x dy/dx = dy/du x du/dx = 2u sec2x = 2 tan x sec2x
How do you simplify tanx plus 1 sqaured?
I assume you mean (tanx+1)^2 In which case, (tanx+1)^2=tan2x+2tanx+1
What is the period of y equals tan2x?
The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2
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The answer depends on differentiate from WHAT!
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What is the answer to cot squared x - tan squared x equals 0?
cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
