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What is average of first 100 even numbers?

The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.


What is formula to find sum of n even numbers?

There is no formula that will sum n even numbers without further qualifications: for example, n even numbers in a sequence.


Is it possible to express 0 as three significant numbers?

0.00? 0 times N times N?


Is the sum of two even numbers even or odd?

The sum of two even numbers is always EVENYes.Proof:We can consider an even number as 2*n, and an odd number as 2*n+1.The sum of two even numbers would be 2*n+2*m=2*(n+m), an even number.


Why is the sum of four consecutive numbers always even?

If n is the first number, n + n + 1 + n + 2 + n + 3 will be the sum, which is 4n + 6. 4n is always even, and 6 is even. Therefore, the sum of four consecutive numbers is always even.


What is the formula to find out the sum of first n even numbers?

n*(n+1)


What is the form of even numbers?

the form of even numbers is 2n example;2*n means 2*any natural number 2*4=8 8 is an even n


What is the formula to find sum of n even numbers?

Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]


Why does n squared plus n always add up to an even number?

=n^2 +n =n(n+1) since either n or n+1 has to be even (consecutive numbers) the answer always is an even number


What is the probability of rolling an even with one roll of a numbers cube. express the probability as a decimal.?

What is the probability of rolling an even with one roll of a numbers cube.


How would you find the sum of the first 50 even numbers?

Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550


The average of four consecutive even number is 27 the largest of these number?

The largest is 30. Let the largest of the four consecutive even numbers be n; then the four consecutive even numbers are (n - 6), (n - 4), (n - 2) & n, and: ((n - 6) + (n - 4) + (n - 2) + n) ÷ 4 = 27 ⇒ (4n - 12) ÷ 4 = 27 ⇒ n - 3 = 27 ⇒ n = 30