Your factors must begin 3x and x to give 3x2. The factors of 12 are 1/12, 2/6 and 3/4. Which pair, together with 3x and x, can add to -5? 3 and 4 seem to fit the bill:
(3x + 4)(x - 3)
It is: (3x+4)(2x-3) when factored
3x2-x-2 = (3x+2)(x-1)
It is: (2x+3)(3x-8) when factored
20x2 - 3x + 10 does not have any real factors.
(18x^(2) - 3x) '3x' is a common factor to both terms , so 'take it out'. Hence 3x(6x - 1) Fully factored.
3x squared minus 25x minus 28
x(3x - 2)
(18x^(2) - 3x) '3x' is a common factor to both terms , so 'take it out'. Hence 3x(6x - 1) Fully factored.
(x-3)(3x+1)
(3x + 1)(x - 5)
(3x + 8)(3x - 8)
It is: (3x+4)(2x-3) when factored
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
3x2-x-2 = (3x+2)(x-1)
(x + 2)(3x - 1)(3x + 1)
It is: (2x+3)(3x-8) when factored
3x^2 -14x +15 = (3x-5)(x-3)