(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1
To factor 4x^2 - 21x + 5, we look for two binomials in the form (Ax + B)(Cx + D) that multiply to give 4x^2 - 21x + 5. We can determine the values of A, B, C, and D by examining the factors of 4 and 5. The factored form is then (4x - 1)(x - 5).
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)
y = 3x + 21x2 = 3x(1 + 7x)
21x + 9 = 180 21x = 180 - 9 21x = 171 x = 171/21 x = 8.143
It is: 3x*(x+7)
x
Make it equal zero by subtracting 21x from both sides. 20x2 - 21x - 5 factors to (4x - 5)(5x + 1)
(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
3(7x + 11)
(2x - 1)(x - 10)
(x - 8)(x - 13)
To factor 4x^2 - 21x + 5, we look for two binomials in the form (Ax + B)(Cx + D) that multiply to give 4x^2 - 21x + 5. We can determine the values of A, B, C, and D by examining the factors of 4 and 5. The factored form is then (4x - 1)(x - 5).
(5x-6)(x-3)
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)