To factor the expression 81r + 48rt, we first find the greatest common factor of the two terms, which is 3r. We then factor out this common factor to get 3r(27 + 16t). This is the factored form of the expression 81r + 48rt.
(a + 2b)(a + 2b)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
The only factor is 2. 2*(t3 + 2t2 + 4x)
Two is a prime factor of that equation.
You can factor a five out of 15 plus 5x. Therefore, 15 plus 5x factors out to 5(3+x). Hope it helps :)
3r(16s + 27)
Aound $100
5m
The other factor is 1.
(a + 2b)(a + 2b)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
factor the trinomial 16x^2+24x+9
The ANSI code 81R protection scheme is used primarily in electrical power systems for the protection of generators and motors against out-of-step conditions. It detects when a machine is losing synchronism with the power system, which can occur during system disturbances or faults. By monitoring the phase relationship between voltage and current, the 81R scheme can initiate disconnection of the equipment to prevent damage and ensure system stability. This protection is commonly implemented in substations and industrial facilities with large rotating machinery.
You can't factor it
That does not factor neatly.
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
1