i believe your equation is this...
x4 - 7x3 + 10x2
just take out everything that is the same. you can not take out any numerical values. you can only take out the variables. so take out 2 x's
x2(x2 - 7x + 10)
this is the factored form. to put it back into the form you originally had just multiply the x2 by each term inside the parenthesis.
Note: in case you didn't know x2 is the same as x multiplied by x which means you have 2 x's. Also, x3 is the same as x times x times x since you have three x's. And x4 is the same as x times x times x times x since you have four x's. And this can be done for x5 x6 ... and so on.
(5x - 4)(2x + 3)
4x3+10x2+2x+5= (2x+5)(2x2+1)
10x2 - 20xz + 15xy = 5x (2x - 4z + 3y)
To factor: 10x2 + 27x - 28 Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor: = 10x2 + 35x - 8x - 28 = 5x(2x + 7) - 4(2x + 7) = (5x - 4)(2x + 7)
(10x + 3)(x - 1)
(5x - 4)(2x + 3)
It can't be factored because its discriminant is less than zero.
10x2 + 101x + 10 = (10x + 1)(x + 10)
If that's - 94x, the answer is 2(3x - 10)(x2 + 5x + 1)
4x3+10x2+2x+5= (2x+5)(2x2+1)
10x2-5x-5 = (10x+5)(x-1)
The answer is 21
This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.
5x(2x - 3)
10x2 - 20xz + 15xy = 5x (2x - 4z + 3y)
Multiply all terms by 10 it then becomes 10x2+13x+4 = (5x+4)(2x+1) when factored.
(10x + 3)(x - 1)