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Suppose the revenue equation is of the form R = ax2 + bx + c where a, b and c are constants and x is the variable.
To have a maximum, either a must be negative or x must lie within fixed limits.
If a is negative then the maximum revenue is attained when x = -b/(2a). That is, find the value of R when x = -b/(2a).
If a is positive, then find the value of R when x is at each end point of its domain. One of them will be larger and that is the maximum value of the revenue.
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