It's simpler than you might think..
The general equation you need is this:
a+b+c 4a+2b+c 9a+3b+c 16a+4b+c
3a+b 5a+b 7a+b
2a 2a
Basically, the second row down is the difference between the terms of the sequence itself (top row). And the 3rd row down is the differences of the differences (:P).
I'm not good enough with words to explain how to find the nth term so I'll give you an example:
3 7 15 27 43
4 8 12 16
4 4 4
First, you need to know this formula:
2a=diff. of diff. (4 in this example)
3a+b= 1st of the differences (4 in this example)
A+B+C= 1st term (3 in this example)
So let's work it out:
2a=4
(so) a=2
3a+b= 4
(3a would be 3 times 2 so) 6+b=4
(To get from 6 to 4 you need to minus two so) b= -2
(To get to c you need a+b and then work out the difference of that and the 1st term.)
a+b= 0
(2-2= 0)
(The difference of the first term and a+b gives you c)
3-0= 3
c=3
Hope this has helped :S
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To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
0.5n(n+1)
Wow you really can't spell.
1, 3, 6, 10, ... The nth term is n*(n+1)/2