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To find the equation of the axis of symmetry for a parabola given in the standard form (y = ax^2 + bx + c), you can use the formula (x = -\frac{b}{2a}). This value of (x) represents the vertical line that divides the parabola into two mirror-image halves. If the parabola is represented in vertex form (y = a(x-h)^2 + k), the axis of symmetry is simply the line (x = h).
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How do you find the gradient of a quadratic equation?
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
What is the equation of the axis of symmetry plus x2-3?
-1
How do you find the equation of the axis of symmetry of y equals 2x plus 2 plus 4x plus 2?
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
What is the axis of symmetry for y-x2 2x-4?
To find the axis of symmetry for the quadratic equation ( y = -x^2 + 2x - 4 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a ) and ( b ) are the coefficients from the equation in standard form ( y = ax^2 + bx + c ). Here, ( a = -1 ) and ( b = 2 ). Plugging in the values, the axis of symmetry is ( x = -\frac{2}{2 \times -1} = 1 ). Thus, the axis of symmetry is ( x = 1 ).
How do you determine if a graph is symmetric with respect to the x axis y axis or origin?
To determine if a graph is symmetric with respect to the x-axis, check if replacing (y) with (-y) in the equation yields an equivalent equation. For y-axis symmetry, replace (x) with (-x) and see if the equation remains unchanged. For origin symmetry, replace both (x) with (-x) and (y) with (-y) and verify if the equation is still the same. If the equation holds true for any of these conditions, the graph exhibits the corresponding symmetry.
The equation for the axis of symmetry is?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
What is the axis of symmetry of a quadratic equation?
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
How do you find the gradient of a quadratic equation?
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
What is the equation of the axis of symmetry and the vertex of the graph gx-2x-12x 6?
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
What is the equation of the axis of symmetry plus x2-3?
-1
How do you find the equation of the axis of symmetry of y equals 2x plus 2 plus 4x plus 2?
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
What is the equation of the axis of symmetry of the graph of the equation YXX-5X 6?
X=-b/2a
What is the axis of symmetry for y-x2 2x-4?
To find the axis of symmetry for the quadratic equation ( y = -x^2 + 2x - 4 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a ) and ( b ) are the coefficients from the equation in standard form ( y = ax^2 + bx + c ). Here, ( a = -1 ) and ( b = 2 ). Plugging in the values, the axis of symmetry is ( x = -\frac{2}{2 \times -1} = 1 ). Thus, the axis of symmetry is ( x = 1 ).
Find the vertex and equation of the directri for y2 equals -32x?
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
How do you find the axis of symmetry for a quadratic equation?
Complete the square, then find the value of x that would make the bracket zero ax^2 + bx + c = 0 line of symmetry is x = (-b/2a)
How do you determine if a graph is symmetric with respect to the x axis y axis or origin?
To determine if a graph is symmetric with respect to the x-axis, check if replacing (y) with (-y) in the equation yields an equivalent equation. For y-axis symmetry, replace (x) with (-x) and see if the equation remains unchanged. For origin symmetry, replace both (x) with (-x) and (y) with (-y) and verify if the equation is still the same. If the equation holds true for any of these conditions, the graph exhibits the corresponding symmetry.
What is the equation of axis of symmetry for yx2 5x-12?
12 x 5 = 60
