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What is the formula used to find the axis of symmetry?
The formula to find the axis of symmetry for a quadratic function in the form (y = ax^2 + bx + c) is given by (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. The axis of symmetry passes through the vertex of the parabola and is crucial for graphing the function.
How do you find the y-coordinate vertex of a parabola?
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
How do you find the equation of a axis of symmetry?
To find the equation of the axis of symmetry for a parabola given in the standard form (y = ax^2 + bx + c), you can use the formula (x = -\frac{b}{2a}). This value of (x) represents the vertical line that divides the parabola into two mirror-image halves. If the parabola is represented in vertex form (y = a(x-h)^2 + k), the axis of symmetry is simply the line (x = h).
How do u find the equation of the axis of symmetry and the vertex of the graph of each function for example y x2-8x-9 Plz help i need to know this?
To find the equation of the axis of symmetry for the quadratic function (y = x^2 - 8x - 9), use the formula (x = -\frac{b}{2a}), where (a = 1) and (b = -8). This gives (x = -\frac{-8}{2 \cdot 1} = 4). The vertex can be found by substituting this (x) value back into the original equation: (y = 4^2 - 8(4) - 9 = 16 - 32 - 9 = -25). Thus, the vertex is at the point ((4, -25)) and the axis of symmetry is the line (x = 4).
How do you find the axis of symmetry of the quadratic function.?
The axis of symmetry of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. To find the corresponding (y)-coordinate, substitute the axis of symmetry value back into the quadratic function.
Find the vertex and equation of the directri for y2 equals -32x?
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
What is the formula used to find the axis of symmetry?
The formula to find the axis of symmetry for a quadratic function in the form (y = ax^2 + bx + c) is given by (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. The axis of symmetry passes through the vertex of the parabola and is crucial for graphing the function.
How do you find the axis of symmetry and vertex of y equals x squared plus 6x plus 10?
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
How do you find the y-coordinate vertex of a parabola?
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
Find the equation of the axis symmetry and the coordinates of the vertex of the graph of each function for y equals 2x plus 4?
I'm assuming that you meant y = 2(x^2) +4. If it were only y = 2x +4, then this would be a linear equation and not a parabola. Anyways, use the equation x = -b/2a to find the x-value of your vertex AND your axis of symmetry. (Given the standard equation y = a(x^2) + bx + c) So, x = -0/2(2) - x = 0 (Axis of Symmetry) Now plug 0 back into your equation to find your y-value of your vertex. y = 2(0^2)+4 y=0 + 4 y = 4 Therefore Vertex = (0,4)
How do u find the equation of the axis of symmetry and the vertex of the graph of each function for example y x2-8x-9 Plz help i need to know this?
To find the equation of the axis of symmetry for the quadratic function (y = x^2 - 8x - 9), use the formula (x = -\frac{b}{2a}), where (a = 1) and (b = -8). This gives (x = -\frac{-8}{2 \cdot 1} = 4). The vertex can be found by substituting this (x) value back into the original equation: (y = 4^2 - 8(4) - 9 = 16 - 32 - 9 = -25). Thus, the vertex is at the point ((4, -25)) and the axis of symmetry is the line (x = 4).
How do you find the axis of symmetry of the quadratic function.?
The axis of symmetry of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. To find the corresponding (y)-coordinate, substitute the axis of symmetry value back into the quadratic function.
How do you find the axis of symmetry?
X= -b / 2a
Tell whether the graph opens up or down Find the coordinates of the vertex Write an equation of the axis of symmetry for the equation y equals 2x2 plus 3x plus 6?
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
The equation for the axis of symmetry is?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
How do you find the x intercepts using the vertex and y intercept?
It depends on the vertex of what!
What do you know about a function that is made up of ordered pairs in such a way that the same y-value appears in a correspondence with two different x-values?
For example, y = ax2 + bx + c (the equation of a parabola). Every parabola has an axis of symmetry and the graph to either side of the axis of symmetry is a mirror image of the other side. It means that if we know a point on one side of the parabola, we can find its symmetric point to the other side, based on the axis of symmetry. Those symmetric points have opposite x-coordinate values, and the same y-coordinate value. The vertex only is a single point which lies on the axis of symmetry.
