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Suppose the sum is SS = 100 + 101 + ... + 998 + 999

Also, writing it in reverse order gives

S = 999 + 998 + ... + 101 + 100

so, adding the two together,

2S = 1099 + 1099 + ... + 1099 + 1099 where there are 900 such terms.

So S = 1099*900/2 = 494550.

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Q: How do you find the sum all of three digit positive integers?
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