answersLogoWhite

0

You sit in the sun for about 2-3-4 hours.

No! Do not sit in the sun for that long. You could get dehydrated and get sun poisioning! Use tanning lotion is the way i find most easiest OR go to a tanning bed.

Agreed, don't sit in the sun for that long- though is there even such a thing as sun poisoning?. Personally I prefer pale skin, but each to their own. If you can get a tan, sit in the sun for a little while, but drink enough water and wear sunscreen. A lot of people think this stops you from getting a tan, but it doesn't; it helps protect your skin while you get a tan. If you find getting a tan hard, you might have to get a fake tan. A tanning bed will not help if you can't get a tan normally, it will only further damage your skin.

User Avatar

Wiki User

14y ago

Still curious? Ask our experts.

Chat with our AI personalities

JudyJudy
Simplicity is my specialty.
Chat with Judy
ReneRene
Change my mind. I dare you.
Chat with Rene
CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach

Add your answer:

Earn +20 pts
Q: How do you get a tan?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Math & Arithmetic

Tan 9 plus tan 81 -tan 27-tan 63?

tan(9) + tan(81) - tan(27) - tan(63) = 4


If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?

tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).


What is tan 45?

tan 45 = 1


How do you solve for the exact value of tan 2 pi?

tan 2 pi = tan 360º = 0


How do you verify the identity of cos θ tan θ equals sin θ?

To show that (cos tan = sin) ??? Remember that tan = (sin/cos) When you substitute it for tan, cos tan = cos (sin/cos) = sin QED