To graph a line given its equation in slope-intercept form, which is (y = mx + b), identify the slope (m) and the y-intercept (b). Start by plotting the y-intercept on the y-axis at the point (0, b). Then, use the slope to determine another point by rising (or falling) and running from the y-intercept, and plot this second point. Finally, draw a straight line through the two points to complete the graph.
If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.
To determine the equation of the line in a graph, you need two key pieces of information: the slope (m) and the y-intercept (b). The general form of a linear equation is ( y = mx + b ). If you can identify these values from the graph, you can then write the specific equation for the line. Without the graph, I can't provide the exact equation.
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
When you are trying to graph an equation.
Yes
y = 2x + 1.
On my graphing calculator, a TI84 Plus, I can enter the equation into the Y= (a button) and then graph it by hitting the Graph button.
If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.
A linear equation has the form of mx + b, while a quadratic equation's form is ax2+bx+c. Also, a linear equation's graph forms a line, while a quadratic equation's graph forms a parabola.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
no the graph will be written in slope intercept form or y=mx+b
To determine the equation of the line in a graph, you need two key pieces of information: the slope (m) and the y-intercept (b). The general form of a linear equation is ( y = mx + b ). If you can identify these values from the graph, you can then write the specific equation for the line. Without the graph, I can't provide the exact equation.
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
When you are trying to graph an equation.
Yes
Normally a quadratic equation will graph out into a parabola. The standard form is f(x)=a(x-h)2+k
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0