You subtract X from both sides, in which u get y=x-4; u should be able to graph that
First convert it to Y= y-x+4=0 y=x-4 The graph has a slope of 1 and the y-intercept is (0,-4)
If: x-y = 4 and x-3y = 4 Then by solving the simultaneous equations: x = 4 and y = 0 So the lines intersect at (4, 0) which will be a vertical straight line
The line x = 4 is a verticle line because, in a standard x-y graph, where x increases to the right and y increases upwards, the graph x = 4 is all points y, where x is 4. That is a verticle line, with infinite slope.
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
You subtract X from both sides, in which u get y=x-4; u should be able to graph that
It is y = x + 4
First convert it to Y= y-x+4=0 y=x-4 The graph has a slope of 1 and the y-intercept is (0,-4)
When y=4, x=8/5
X = 4 is a vertical line, 4 units to the right of the y-axis.
The graph of the function f(x) = 4, is the horizontal line to the x=axis, which passes through (0, 4). The domain of f is all real numbers, and the range is 4.
6
If: x-y = 4 and x-3y = 4 Then by solving the simultaneous equations: x = 4 and y = 0 So the lines intersect at (4, 0) which will be a vertical straight line
The line x = 4 is a verticle line because, in a standard x-y graph, where x increases to the right and y increases upwards, the graph x = 4 is all points y, where x is 4. That is a verticle line, with infinite slope.
Upwards.
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.