I guess you are meaning the standard trigonometric ratios regarding the cos/sin/tan of angles in a right angled triangle.
I was taught this little rhyme:
Two Old Arabs
Soft Of Heart
Coshed Andy Hatchett
Using the initial letters of each of the words:
T O A
S O H
C A H
Gives:
Tan = Opposite / Adjacent
Sin = Opposite / Hypotenuse
Cos = Adjacent / Hypotenuse
Later I met the nonsense word SOHCAHTOA (pronounced So-ka-toe-ah or Sock-a-toe-ah) in which the letters are the ratios as before and which is slightly more useful in that in that order it gives a reminder that Sin/Cos = Tan. However, it does require being able to spell the unusual "word".
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To show that (cos tan = sin) ??? Remember that tan = (sin/cos) When you substitute it for tan, cos tan = cos (sin/cos) = sin QED
'csc' = 1/sin'tan' = sin/cosSo it must follow that(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2
(sin(x)cot(x) - cos(x))/tan(x)(Multiply by tan(x)/tan(x))sin(x) - cos(x)tan(x)(tan(x) = sin(x)/cos(x))sinx - cos(x)(sin(x)/cos(x))(cos(x) cancels out)sin(x) - sin(x)0
It just simplifies down to 1=1. You have to use your trig identities... tan=sin/cos cot=cos/sin thus tan x cot= (sin/cos) (cos/sin) since sin is in the numerator for tan, when it is multiplied by cot (which has sin in the denominator) both of the signs cancel and both now have a value of 1. The same happens with cos. so you get 1 x 1=1 so there is your answer. just learn your trig identities and you will understand
The definition of tan(x) = sin(x)/cos(x). By this property, cos(x)tan(x) = sin(x).