Use Euclid's formula.
Take any two integers m and n that are coprime and let m > n (if not, just swap them around).
Then
a = m2 - n2
b = 2mn
and
c = m2 + n2
form a primitive Pythogorean triple.
And since (a, b, c) is a Pythagorean triple then so is (k*a, k*b, k*c) for any integer k, except that the latter is not primitive.
If you mean 3, 4 and 5 then yes it is a Pythagorean triple
You seem to have squashed the numbers together but 4, 3 and 5 make up a Pythagorean triple.
No
The triple is: 20, 21 and 29
The integers 3 and 4 form part of the 3-4-5 Pythagorean triple.
No, the multiple of any random triple is not a Pythagorean triple.
Nearly but not quite a Pythagorean triple
If you mean 3, 4 and 5 then yes it is a Pythagorean triple
You seem to have squashed the numbers together but 4, 3 and 5 make up a Pythagorean triple.
There are infinitely many Pythagorean triples. To find a Pythagorean triple take two positive integers x, y with x > y. A Pythagorean triple is of the form x2 - y2, 2xy, x2 + y2.
What is the value of x if (13, 84, x) is a Pythagorean triple?
Indeed they do, it is a Pythagorean Triple: 6*6 + 8*8 = 10*10. (62 + 82 = 102, 36 + 68 = 100, 100 = 100) The "basic" Pythagorean Triple of a 3, 4, 5 triangle works out like this: 32 + 42 = 52 9 + 16 = 25 25 = 25 Your triangle, the 6, 8, 10, figure, is a "doubling" of the cited "basic" triple, and any multiple of a Pythagorean Triple will also be another Pythagorean Triple, and a right triangle.
If p and q are integers, then a = p2 - q2 b = 2pq, and c = p2 + q2 form a Pythagorean triple. Furthermore, if p and q are co-prime then the triple is primitive Pythagorean.
A Pythagorean triple is three positive integers a, b, and c, such that a^2 + b^2 = c^2. A well known Pythagorean triplet is (3,4,5). If (a, b, c) is a Pythagorean triplet, then so is (ka, kb, kc) for any positive integer k.
34
No.
No