It isn't clear what you mean with "by". Are you multiplying 1 by secx, or perhaps dividing? Also, is the multiplication (or division) only by sec x, or by the sum of secx + cos x?
-x-6-(-11x) + (-1) Remove the brackets: -x-6+11x-1 Collect and simplify like terms: 10x-7 A - - is equal to a +
8 plus 4 minus 12 divided by 1 is 0.
2c
x = 1 1/2 = [14 dividedby (6x - 2) ] - [6 dividedby (3x - 1) ]
This is a trigonometric integration using trig identities. S tanX^3 secX dX S tanX^2 secX tanX dX S (secX^2 -1) secX tanX dX u = secX du = secX tanX S ( u^2 - 1) du 1/3secX^3 - secX + C
secx is the inverse of cosx. secx=1/cosx. A secant is also a line drawn through the graph that touches two points on a function.
4 divided by 9 minus 1 divided 12?
It isn't clear what you mean with "by". Are you multiplying 1 by secx, or perhaps dividing? Also, is the multiplication (or division) only by sec x, or by the sum of secx + cos x?
6 divided by 11 minus 1 divided by 2 equals?
2
-x-6-(-11x) + (-1) Remove the brackets: -x-6+11x-1 Collect and simplify like terms: 10x-7 A - - is equal to a +
-3
1/2 - 2 = -1.5
8 plus 4 minus 12 divided by 1 is 0.
2c
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.