3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
2b2 + 8 para b = -3
3c-7 = -4
The solution (not sum) to the equation 21 = 3c + 6 is as follows:21 = 3c + 621 - 6 = 3c + 6 - 615 = 3c3c = 153c/3 = 21/3c = 7
3c x 8e = 24
3
11(2b2 + 21)
6abc
(a2+2b2-2ab)(a2+2b2+2ab)
Oh, dude, you're hitting me with some math lingo! So, like, the factor of 3c would just be 3, because it's the number that divides evenly into 3c. It's like the cool friend that 3c can always rely on to hang out with.
24a + b2 + 3a + 2b2= 27a + 3b2
do you mean 12a3 - 5a2b - 2b2 ?? = 12a3 + 8a2b - 3a2b - 2b2 then group 1st 2 terms and last 2 and use GCF = (12a3 + 8a2b) + ( - 3a2b - 2b2) = 4a2(3a + 2b) + (-b)(3a2 +2b) not much help, but that's all folks
We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
2b2 + 8 para b = -3
3c-7 = -4
2y-3c = -1