n nn n
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3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
3c-7 = -4
2b2 + 8 para b = -3
The solution (not sum) to the equation 21 = 3c + 6 is as follows:21 = 3c + 621 - 6 = 3c + 6 - 615 = 3c3c = 153c/3 = 21/3c = 7
3c x 8e = 24