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What are 3 equivalent fractions to 4 out of 7?
if you do the same action to the top and bottom of a fraction it is equivalent. 4/7 = 8/14 = 12/21 x2 x3 etc.
How do you solve 4n minus 7n equals 21?
4n - 7n = 21(4-7) n =21-3n = 21divide both sides by -3n = -7
How do you find the solutions of x3-12x plus 7?
Since that isn't an equation, there is really nothing to solve.
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
Solve 3m-5 equals 7-21?
3m-5 = 7-21 3m = 7-21+5 3m = -9 m = -3
What are 3 equivalent fractions to 4 out of 7?
if you do the same action to the top and bottom of a fraction it is equivalent. 4/7 = 8/14 = 12/21 x2 x3 etc.
How do you solve 6 21 b 6 21 b?
how to solve 7 + p = p +7
How do you solve 4n minus 7n equals 21?
4n - 7n = 21(4-7) n =21-3n = 21divide both sides by -3n = -7
How do you solve x over 4 - x over 7?
-3
How do you solve X3 x X4?
X3xX4=X3+4=X7 this is the correct answer.
How do you find the solutions of x3-12x plus 7?
Since that isn't an equation, there is really nothing to solve.
What is 3 4ths of 28?
You can solve this one by asking what is 28 divided by 4? 28/4 = 7. So 7 x 3 = 21. So 3/4th of 28 is 21.
How do you solve the equation for x -4 over 3x equals 1 over 7?
x = 7 7-4/3 x 7 = 1/7 3/21 = 1/7
How to solve 7 minus one half minus one and one fourth?
21/47 - 1/2 - 1 1/4:= 7 - 1/2 - 5/4= (28- 2- 5)/4= 21/4
How much is (4 plus 3)3?
(4+3)3 → Using order of operations, solve the bracket first. (7)3 → Multiply 21
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
2x3 - 7 plus 5x2 - x3 plus 3x - x3?
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
