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Well, honey, when you're multiplying those bad boys X3 and X4, you just add the exponents because they have the same base X. So, X3 x X4 is the same as X(3+4), which simplifies to X7. Easy peasy lemon squeezy!
To solve X^3 x X^4, you add the exponents since you are multiplying like bases. This results in X^(3+4) = X^7. So, X^3 x X^4 = X^7.
Oh, dude, solving X3 x X4 is like, super easy. You just add the exponents together, so X3 x X4 is X7. It's like combining powers, you know? Math can be fun when you don't overthink it.
X3 x x4 = x3 + 4 =x7
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What is the integral of x3 ex4 dx?
∫x3ex4 dx = 1/4ex4 + c To solve, let y = x4, then: dy = 4x3 dx ⇒ 1/4dy = x3 dx ⇒ ∫x3ex4 dx =∫ex4 x3 dx = ∫ey 1/4 dy = 1/4ey + c but y = x4, thus: = 1/4ex4 + c
How do you write an expression using a single exponent?
For example, (x3)(x4) = (x3+4) = x7 Also, (x5)2 = x(5)(2) = x10
how do i solve this 5x2 + 3x2 – x3 + 2x3 + 10x4 – 5x4?
x2 • (5x2 + x + 8)
Find the requested value If p x equals 20x5 - 20x4 plus 24x2 and q x equals 4x2 find p over q x?
To find p(x) / q(x), we first need to substitute the expressions for p(x) and q(x) into the formula. So, p(x) = 20x^5 - 20x^4 + 24x^2 and q(x) = 4x^2. Therefore, p(x) / q(x) = (20x^5 - 20x^4 + 24x^2) / 4x^2. Simplifying this expression, we get 5x^3 - 5x^2 + 6.
What is the pattern rule for this pattern 1 3 2 6 5 15 14 42 41?
The answer is (no.) x3 = (no. 2) - 1 = (no. 3) x3= (no.4) x4 and so on... 1 x 3 = 3 - 1 = 2 x 3 = 6 - 1 = 5 x 3 = 15 - 1 = 14 x 3 = 42 - 1 = 41. :D Hope i helped
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
What is the Greatest Common Factor of x4 and x3?
Greatest common factor of x4 and x3 is x3.
How can you demonstrate that the function x3 is in the set o(x4)?
To demonstrate that the function x3 is in the set o(x4), you can show that the limit of x3 divided by x4 as x approaches infinity is equal to 0. This indicates that x3 grows slower than x4, making it a member of the set o(x4).
What is the answer to x4 plus x3 minus 14x2 plus 4x plus 6 divided by x minus 3?
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
X4-x3 plus X2 -X plus 1?
It is a polynomial of the fourth degree in X.
How do you factor x raised to the 5th minus 1?
(x - 1)(x4 + x3 + x2 + x + 1)
Antiderivative of x cubed divided by 3?
f'(x) = x^(3) / 3 Hence f(x) = 3x^(2) / 3 +C f(x) = x^(2) + C ' The '3' cancels out. The 'C' is a constant that comes with antoderivation.
Express polynomial -x3 plus x4 plus x in standard form?
x^4-x^3+x
What is the derivative of x to the 4th over 4?
d/dx(x4/4) = x3
How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
How do you factor x to the fifth minus one?
x5-1 = (x - 1)(x4 + x3 + x2 + 1)
