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X3 x x4 = x3 + 4 =x7

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X12

Lvl 1

X12

Q: How do you solve X3 x X4?

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p x = 20 x5 - 20 x4 + 24 x2 q x = 4 x2 p = 20 x4 - 20 x3 + 24 x, if xis not equal to 0 p / qx = ( 20 x4 - 20 x3 + 24 x) / (4 x2) = (5 x4 - 5 x3 + 6 x) / x2 So p / qx = 5 x2 - 5 x + 6/x if x is not equal to 0

∫x3ex4 dx = 1/4ex4 + c To solve, let y = x4, then: dy = 4x3 dx ⇒ 1/4dy = x3 dx ⇒ ∫x3ex4 dx =∫ex4 x3 dx = ∫ey 1/4 dy = 1/4ey + c but y = x4, thus: = 1/4ex4 + c

For example, (x3)(x4) = (x3+4) = x7 Also, (x5)2 = x(5)(2) = x10

x2 • (5x2 + x + 8)

The answer is (no.) x3 = (no. 2) - 1 = (no. 3) x3= (no.4) x4 and so on... 1 x 3 = 3 - 1 = 2 x 3 = 6 - 1 = 5 x 3 = 15 - 1 = 14 x 3 = 42 - 1 = 41. :D Hope i helped

Related questions

x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.

Greatest common factor of x4 and x3 is x3.

The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2

(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)

It is a polynomial of the fourth degree in X.

(x - 1)(x4 + x3 + x2 + x + 1)

x4/12 since derivative of x4/12 is 4x3/12 or x3/3

x^4-x^3+x

d/dx(x4/4) = x3

x3 6x2-x-30

x5-1 = (x - 1)(x4 + x3 + x2 + 1)

p x = 20 x5 - 20 x4 + 24 x2 q x = 4 x2 p = 20 x4 - 20 x3 + 24 x, if xis not equal to 0 p / qx = ( 20 x4 - 20 x3 + 24 x) / (4 x2) = (5 x4 - 5 x3 + 6 x) / x2 So p / qx = 5 x2 - 5 x + 6/x if x is not equal to 0