This depends on wether you want your answer in radians or degrees. If you want the answer in degrees, the highest and lowest point of the sin graph wil always be 90, 270, 450... and crosses the zero point at 180, 360, 540... If you want your answer in radians, the graph crosses the zero point, at pi, 2 pi, 3 pi... and has it's highest/lowest point at 1/2 pi, 1 1/2 pi, 2 1/2 pi...
Do sin(x), square it, and then multiply it by two.
sin7x-sin6x+sin5x
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5
You cannot. sin(n)/n is an expression, not an equation. An expression cannot be solved.
sin[cos-1(x)] is an expression; it is not an equation (nor inequality). An expression cannot be solved.
Do sin(x), square it, and then multiply it by two.
sin7x-sin6x+sin5x
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5
You cannot. sin(n)/n is an expression, not an equation. An expression cannot be solved.
sin[cos-1(x)] is an expression; it is not an equation (nor inequality). An expression cannot be solved.
There is nothing to solve in this equation because there is no =. If you accidentally omitted what the expression equals then resubmit it and I'll be happy to look at it
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
Oh, what a happy little math question we have here! To solve arcsin(2/3), you simply take the inverse sine of 2/3, which is approximately 41.81 degrees. Remember, math is just like painting - take it one step at a time and enjoy the process of finding the answer.
1
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
How do you solve ln|tan(x)|=ln|sin(x)|-ln|cos(x)|? Well you start by........
Since sin(a)=opposite/hypotenuse, the reciprocal function is that function which is equal to hypotenuse/opposite. This is "cosecant", or csc(a). The reciprocal of sin(a) is csc(a). I will solve all your math problems. Check my profile for more info.