How do you solve log2 8 plus log232?

Answer 1

To solve ( \log_2 8 + \log_2 32 ), you can use the property of logarithms that states ( \log_b a + \log_b c = \log_b (a \cdot c) ). First, calculate ( \log_2 8 ), which is 3 because ( 2^3 = 8 ), and ( \log_2 32 ), which is 5 because ( 2^5 = 32 ). Therefore, ( \log_2 8 + \log_2 32 = 3 + 5 = 8 ). Alternatively, you could find ( \log_2 (8 \cdot 32) = \log_2 256 = 8 ) directly.