x-2 = 14
x = 14+2
x = 16
The equation is -x2 - 4 = 14 or -x2 = 18 which is the same as x2 = -18. That is the quadratic equation.
(2x)ysquared
Take the square root of both sides of the equation
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
(4 ± i2) where i2 = -1
The equation is -x2 - 4 = 14 or -x2 = 18 which is the same as x2 = -18. That is the quadratic equation.
(2x)ysquared
Take the square root of both sides of the equation
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
(4 ± i2) where i2 = -1
Factor the original equation to get (x-7)(x+2)=0, so x=7 or x=-2
X2 = k Take square root each side. X = (+/-) sqrt(k) ============
it is not an equation (there no equality in it!)
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
Equals anything... x is a variable. If that equation was set equal to zero then you could solve for x, but that is not what you have asked.
The quadratic formula cannot be used to solve an equation if the coefficient of the equation's x2-term is 0.