The equation is -x2 - 4 = 14 or -x2 = 18 which is the same as x2 = -18. That is the quadratic equation.
(2x)ysquared
Take the square root of both sides of the equation
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
(4 ± i2) where i2 = -1
The equation is -x2 - 4 = 14 or -x2 = 18 which is the same as x2 = -18. That is the quadratic equation.
(2x)ysquared
Take the square root of both sides of the equation
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
(4 ± i2) where i2 = -1
Factor the original equation to get (x-7)(x+2)=0, so x=7 or x=-2
X2 = k Take square root each side. X = (+/-) sqrt(k) ============
it is not an equation (there no equality in it!)
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
x - x2 - 9x + 14 = 0 ; whence, x2 + 8x = 14 , x2 + 8x + 16 = 30 , and x + 4 = ±√30 . Therefore, x = ±√30 - 4 .
Equals anything... x is a variable. If that equation was set equal to zero then you could solve for x, but that is not what you have asked.