x2 + 4x - 3 = 0 add 3 to both sides
x2 + 4x = 3 add 22 to both sides to complete the square
x2 + 4x + 22 = 7 form the square
(x + 2)2 = 7 take the square root of both sides
x + 2 = ± √7 subtract 2 to both sides
x = -2 ± √7
x = -2 + √7 or x = -2 - √7
It is: 3x2+6x-11 = 0
That factors to (a + 1)(a + b) a = -1, -b b = -a
(x-3)(x-2)
(x - 3)(x + 5)
x = 25 / 3squared + 5
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
It is: 3x2+6x-11 = 0
That factors to (a + 1)(a + b) a = -1, -b b = -a
X=1
(x-3)(x-2)
(x - 3)(x + 5)
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
x = 25 / 3squared + 5
2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222
104
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
Not sure how to put it. The Pythagorean therom states that a squared plus b squared equals c squared. Aren't a, b and c all variables?