Wiki User
∙ 12y agoThe slope increases.
Wiki User
∙ 12y agoacceleration.
A distance vs time squared graph shows shows the relationship between distance and time during an acceleration. An example of an acceleration value would be 3.4 m/s^2. The time is always squared in acceleration therefore the graph can show the rate of which an object is moving
That's unusual. I guess your teacher is trying to make you think a bit. It's a good mental exercise, though. You may recall that the units of acceleration are meters per second squared. That gives you a clue right there. And if you knew Calculus, you'd know that acceleration is the second derivative of distance, s, with respect to time, t: d2s/dt2. So, by now you're probably getting the feeling that the slope of a distance-time squared graph has something to do with acceleration. And you'd be right. Just as the slope of a velocity-time graph is acceleration, the slope of a distance-t2 graph is acceleration. Well, not quite. It's actually ONE HALF the acceleration.
Since distance is 1/2 at^2 where a is acceleration, it represents one half of the acceleration
The constant acceleration
No. The slope of the distance-time graph is the change in distance per unit of time - otherwise known as speed. Acceleration is the slope of the speed time graph.
acceleration
Equal to the acceleration of the object that is moving through distance in time. * * * * * No. The slope of the distance-time graph is the change in distance per unit of time - otherwise known as speed.
The slope at any point is the velocity, so you can construct a graph of that. The slope at any point on that graph is the acceleration. So you can construct a graph of that. The slope at any point on that is the rate of change of acceleration. And so on.
Slopes give you the rate of change. On a distance vs. time graph the rate of change (i.e. the slope) is the velocity. On a Velovity vs. Time graph the rate of change is the acceleration. etc.
the slope of a speed-time graph is acceleration this slope is change in speed divided by change in time *Twinky~
No, the slope of a speed-versus-time graph represents the rate of change of speed, not acceleration. Acceleration is represented by the slope of a velocity-versus-time graph.
The slope of a speed-time graph represents acceleration. A steeper slope indicates a greater rate of change in speed, which means higher acceleration. Conversely, a shallower slope indicates lower acceleration.
Acceleration can be obtained from a velocity line graph by calculating the slope of the line at a particular point. The slope of the line represents the rate of change of velocity, which is the acceleration. The steeper the slope, the greater the acceleration.
Acceleration can be found by computing the slope of a velocity vs. time graph. Acceleration is the rate of change of velocity over time, so the slope of a velocity vs. time graph represents this change in velocity.
To find acceleration from a speed-time graph, you need to calculate the slope of the speed-time graph. The slope at any point on the speed-time graph represents the acceleration at that specific time. If the speed-time graph is linear, then the acceleration will be constant. If the speed-time graph is curved, you can find the acceleration by calculating the slope of the tangent line at a specific point.
No, acceleration is the rate of change of velocity with respect to time. It is the derivative of the velocity function, not the slope of the velocity vs. time graph. The slope of the velocity vs. time graph represents the rate of change of velocity, not acceleration.